document.write( "Question 635070: two silver alloys contain 40% and 30% silver. how many kilograms of each alloy should be mixed to obtain 20 kilograms of 36% SILVER ALLOY? \n" ); document.write( "
Algebra.Com's Answer #400061 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "Alloy I 40 ---------------- x Kg
\n" ); document.write( "Alloy II 30 ------ 20 - x Kg
\n" ); document.write( "Mixture 36 ---------------- 20
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\n" ); document.write( "40x+30 (20-x)= 36*20
\n" ); document.write( "4000x+ 3000(20 -x)= 72000
\n" ); document.write( "4000x+ 60000-3000x= 72000
\n" ); document.write( "4000x- 3000x=72000-60000
\n" ); document.write( "1000 x = 12000
\n" ); document.write( "/ 1000
\n" ); document.write( " x = 12 Kg 40.00% Alloy I
\n" ); document.write( " 8 Kg 30.00% Alloy II
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\n" ); document.write( "m.ananth@hotmail.ca
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