document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=635015>Question 635015</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x + 4 = 19<BR>\n" );
document.write( "3x = 15<BR>\n" );
document.write( "x = 5\r<BR>\n" );
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document.write( "Can you please teach me how to get to the answer x=5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #400060 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=400060\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x + 4 = 19\r<BR>\n" );
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document.write( "we have to keep the variable x on one side of the equation. lets keep it on the left hand side of the equation. 4 has to be moved to the right hand side of the equation.\r<BR>\n" );
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document.write( "How do we remove the 4\r<BR>\n" );
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document.write( "add -4  on both sides\r<BR>\n" );
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document.write( "3x+4 -4 = 19-4<BR>\n" );
document.write( "+4 & -4 cancel off<BR>\n" );
document.write( "3x= 15\r<BR>\n" );
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document.write( "To find the value of x the co efficient of x should be 1\r<BR>\n" );
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document.write( "so we divide both sides by 3\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%283x%2F3%29=%2815%2F3%29 ALIGN=MIDDLE  ALT=\"%283x%2F3%29=%2815%2F3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "x= 5\r<BR>\n" );
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document.write( "m.ananth@hotmail.ca\r<BR>\n" );
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document.write( " </SPAN>\n" );
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