document.write( "Question 635058: An invester invested a total of 3000 dollars into two mutual funds. One fund earned 4% profit while the other earned 2% profit. If the investors total profit was 98 dollars, how much was invested in each fund? \n" ); document.write( "
Algebra.Com's Answer #400058 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Mutual fund I 4.00% per annum ------------- Amount invested =x \n" ); document.write( "Mutual fund II 2.00% per annum ------------ Amount invested = y \n" ); document.write( " 3000 \n" ); document.write( "Interest----- 98 \n" ); document.write( " \n" ); document.write( "Mutual fund I 4.00% per annum ---x \n" ); document.write( "Mutual fund II 2.00% per annum ---y \n" ); document.write( "Credit on both cards \n" ); document.write( "x + 1 y= 3000 -------------1 \n" ); document.write( "Interestto be paid on both \n" ); document.write( "4.00% x + 2.00% y= 98 \n" ); document.write( "Multiply by 100 \n" ); document.write( "4 x + 2 y= 9800.00 --------2 \n" ); document.write( "Multiply (1) by -4 \n" ); document.write( "we get \n" ); document.write( "-4 x -4 y= -12000.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x -2 y= -2200 \n" ); document.write( "divide by -2 \n" ); document.write( " y = 1100 \n" ); document.write( "Mutual fund I 4.00% $ 1900 \n" ); document.write( "Mutual fund II 2.00% $ 1100 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "1900 --------- 4.00% ------- 76.00 \n" ); document.write( "1100 ------------- 2.00% ------- 22.00 \n" ); document.write( "Total -------------------- 98.00 \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |