document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1346>Question 1346</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having problems setting this equation up.  The problem is:  If two cars leave the same location at the same time, And car one is traveling 20 MPH faster than car two in opposite directions, and they are 168 miles apart 1 1/2 hours later...how fast is each one going?  Your help is GREATLY needed.  Thank you!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #400 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=400\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Assume the speed of car one is x mph, <BR>\n" );
document.write( " then the speed of car two is x-2 mph.\r<BR>\n" );
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document.write( " When they travel in the opposite direction,<BR>\n" );
document.write( " distance = sum of two speed * Time, <BR>\n" );
document.write( " So,  168 = (x+x-2)* (3/2) = 3x -3,<BR>\n" );
document.write( " or 3x = 171, x = 57 and x-2 = 55.\r<BR>\n" );
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document.write( " Answer: speed of car 1 is 57 MPH,<BR>\n" );
document.write( "  speed of car 2 is 55 MPH </SPAN>\n" );
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