document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=634932>Question 634932</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the method of substitution to solve the system of linear equations.<BR>\n" );
document.write( "4a=6-b<BR>\n" );
document.write( "4a=2-b\r<BR>\n" );
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document.write( "Could you please show me this in detail.  I just don't understand it.  Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #399996 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=399996\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4a is both 6-b and 2-b. So 6-b = 2-b\r<BR>\n" );
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document.write( "Another way to say it is...\r<BR>\n" );
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document.write( "4a=6-b ... Start with the first equation.\r<BR>\n" );
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document.write( "2-b=6-b ... Replace '4a' with '2-b' (since 4a = 2-b)\r<BR>\n" );
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document.write( "Now solve for b. Then use the solution to find 'a'. </SPAN>\n" );
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