document.write( "Question 634790: A car travelling at a constant spped of 98km/h on a freewaty passes a sign that states that the next town is 80km away.\r
\n" ); document.write( "\n" ); document.write( "a) A second care passes the sign 10 minutes after the first car. If it was travelling at 105km/h, find a model for its distance from the town\r
\n" ); document.write( "\n" ); document.write( "b) What time did the second car pass through the town if the first car passed the sign at 12 noon?
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Algebra.Com's Answer #399988 by ankor@dixie-net.com(22740)\"\" \"About 
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A car traveling at a constant speed of 98km/h on a freeway passes a sign that
\n" ); document.write( " states that the next town is 80km away.
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\n" ); document.write( "a) A second car passes the sign 10 minutes after the first car.
\n" ); document.write( " If it was traveling at 105km/h, find a model for its distance from the town
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\n" ); document.write( "Find how far behind the 2nd car is behind the first when it passes the sign
\n" ); document.write( "Then how far it is from the town at that time
\n" ); document.write( "Convert 10 min to 1/6 hr
\n" ); document.write( "105*\"1%2F6\" = 17.5 km, so it is 17.5+80 = 97.5 km from the town
\n" ); document.write( "let t = travel time of the 2nd car
\n" ); document.write( "d(t) = 97.5 - 105t; an equation for the distance the 2nd car is from town
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\n" ); document.write( "b) What time did the second car pass through the town if the first car
\n" ); document.write( " passed the sign at 12 noon?
\n" ); document.write( "Find the travel time of 2nd car: 97.5/105 = .92857 * 60 = 55.7 min
\n" ); document.write( "Find the travel time of 1st car: 80/98 = .8889 * 60 = 53.3 min
\n" ); document.write( "55.7 - 53.3 = 2.4 min
\n" ); document.write( "If Car 1 arrives at noon, car 2 arrives 2.4 min after noon
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