document.write( "Question 634804: Volume. A flat, square piece of cardboard is used to construct an open box by cutting out squares (measuring 1 foot by 1 foot) from the corners and folding up the resulting edges. If a particular box has a volume of 16 cubic feet, what are the dimensions of the original piece of cardboard? need it pls :( in 2 hours PLS! \n" ); document.write( "
Algebra.Com's Answer #399987 by jim_thompson5910(35256)\"\" \"About 
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Unfortunately 2 hours isn't enough time (usually). The answer/response time varies on this site.\r
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\n" ); document.write( "\n" ); document.write( "Let x = original dimensions\r
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\n" ); document.write( "\n" ); document.write( "Since you're taking 1 ft from each side, you're taking 2*1 = 2 feet from each dimension.\r
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\n" ); document.write( "\n" ); document.write( "So each dimension becomes x-2\r
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\n" ); document.write( "\n" ); document.write( "So the volume is V = 1*(x-2)*(x-2)\r
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\n" ); document.write( "\n" ); document.write( "which becomes\r
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\n" ); document.write( "\n" ); document.write( "V = (x-2)^2\r
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\n" ); document.write( "\n" ); document.write( "Since the volume is 16, we can say\r
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\n" ); document.write( "\n" ); document.write( "(x-2)^2 = 16\r
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\n" ); document.write( "\n" ); document.write( "Now solve for x\r
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\n" ); document.write( "\n" ); document.write( "(x-2)^2 = 16\r
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\n" ); document.write( "\n" ); document.write( "x-2 = sqrt(16)\r
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\n" ); document.write( "\n" ); document.write( "x-2 = 4\r
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\n" ); document.write( "\n" ); document.write( "x = 4+2\r
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\n" ); document.write( "\n" ); document.write( "x = 6\r
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\n" ); document.write( "\n" ); document.write( "So the original box was 6 feet by 6 feet.
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