document.write( "Question 634850: For doing some work ganesh takes 10 days more than john.If both work together they completed the same work in 12 days.Find the number of days if ganesh walks alone \n" ); document.write( "
Algebra.Com's Answer #399955 by ptaylor(2198)\"\" \"About 
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Let x=amount of time it takes John to do the work
\n" ); document.write( "Then John works at the rate of 1/x of the job per day
\n" ); document.write( "x+10=amount of time it takes Ganesh to do the work
\n" ); document.write( "Then Ganesh works at the rate of 1/(x+10) of the job per day
\n" ); document.write( "Together they complete the work in 12 days
\n" ); document.write( "So, together they work at the rate of 1/12 of the job per day
\n" ); document.write( "So our equation to solve is:
\n" ); document.write( " 1/x +1/(x+10)=1/12 multiply each term by 12x(x+10)
\n" ); document.write( "12(x+10)+12x=x(x+10)
\n" ); document.write( "12x+120+12x=x^2+10x collecting like terms, we get
\n" ); document.write( "x^2-14x-120=0 quadratic in standard form and it can be factored
\n" ); document.write( "(x-20)(x+6)=0
\n" ); document.write( "x=20-----------------amount of time it takes John to do the work
\n" ); document.write( "x+10=20+10=30 days----ANSWER-- time it takes Ganesh working alone
\n" ); document.write( "and
\n" ); document.write( "x=-6---------------work is positive---no good\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "1/20+1/30=1/12
\n" ); document.write( "3/60+2/60=1/12
\n" ); document.write( "5/60=1/12
\n" ); document.write( "1/12=1/12\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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