document.write( "Question 58274: How many ounces of pure gold must be added to five ounces of something that is 1% gold in order that the mixture is 6% gold? \n" ); document.write( "
Algebra.Com's Answer #39995 by ankor@dixie-net.com(22740)\"\" \"About 
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How many ounces of pure gold must be added to five ounces of something that is 1% gold in order that the mixture is 6% gold?
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\n" ); document.write( "Let x = amt of pure gold required
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\n" ); document.write( "Write a per cent gold equation. (100% gold is 1.0(x))
\n" ); document.write( "The final amt will be be (x+5)
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\n" ); document.write( ".01(5) + 1.0(x) = .06(x+5)
\n" ); document.write( ".05 + 1x = .06x + .3
\n" ); document.write( "1x - .06x = .3 - .05
\n" ); document.write( ".94x = .25
\n" ); document.write( "x = .266 oz of pure gold required
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\n" ); document.write( "Check:
\n" ); document.write( ".05 + .266 = .06(5.266)
\n" ); document.write( ".05 + .266 = .316, checks out \n" ); document.write( "
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