document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=634780>Question 634780</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a heptagon is 9a^2s ft. The perimeter of a triangle is 6a^6b^2s ft. Find the ratio of the perimeter of the heptagon to the perimeter of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #399929 by </B><A HREF=/tutors/aboutme.mpl?userid=jsmallt9><B>jsmallt9(3758)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jsmallt9><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=399929\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The ratio would be<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=9a%5E2s%2F6a%5E6b%5E2s ALIGN=MIDDLE  ALT=\"9a%5E2s%2F6a%5E6b%5E2s\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now we just reduce the fraction. The s's cancel. A factor of 3 in 9 will cancel with a factor of 3 in 6. And the two factors of a in the numerator will cancel with 2 of the 6 factors of a in the denominator:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F2a%5E4b%5E2 ALIGN=MIDDLE  ALT=\"3%2F2a%5E4b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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