document.write( "Question 634797: Hi, this question has completely stumped me.
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document.write( "Let A,B,C be the angles of a triangle. Show that tanA+tanB+tanC=tanAtanBtanC\r
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document.write( "I've tried using identities to turn it into sin/cos but I got stuck and couldn't go any further.\r
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document.write( "I appreciate your help,\r
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document.write( "Thankyou \n" );
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Algebra.Com's Answer #399910 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! The key is the fact that A, B and C are angles of a triangle. So A+B+C = 180. \n" ); document.write( "Solving this equation for C we get: \n" ); document.write( "C = 180 - (A+B) \n" ); document.write( "So \n" ); document.write( "tan(C) = tan(180-(A+B)) \n" ); document.write( "Using the tan(x-y) formula on the right wide we get: \n" ); document.write( " \n" ); document.write( "Since tan(180) = 0 this simplifies: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Using the tan(x+y) formula on the right side we get: \n" ); document.write( " \n" ); document.write( "which simplifies to \n" ); document.write( " \n" ); document.write( "Remember this equation. We will use it now and again later. \n" ); document.write( "We can substitute the above for tan(C) in the left side of the given equation (which we are trying to prove): \n" ); document.write( " \n" ); document.write( "The right side is one term (of three factors). So it will help if we make the left side one term, too. So we'll get common denominators and add: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "When we add, some of the terms in the numerators cancel: \n" ); document.write( " \n" ); document.write( "leaving: \n" ); document.write( " \n" ); document.write( "The right side has factors of tan(A) and tan(B). So does the left side. So lets factor them out: \n" ); document.write( " \n" ); document.write( "which can be rewritten as: \n" ); document.write( " \n" ); document.write( "And if you look at the third factor and at the equaiton I have asked you to remember, you will see that they are the same. So the third factor is tan(C): \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |