document.write( "Question 634771: Im having trouble factoring polynomials:\r
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document.write( "please show the steps and explain (simply) what changes were made and why they were made between steps:\r
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document.write( "a few examples of what i am having trouble with:\r
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document.write( "(2x^3) + (3x^2) - 8x - 12 = 0\r
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document.write( "(x/(x+2) + (1/4) = 5\r
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document.write( "x^(5/4) - 32 = 0\r
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document.write( "(6x^4) - (23x^2) + 20 = 0 \n" );
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Algebra.Com's Answer #399882 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! (2x^3) + (3x^2) - 8x - 12 = 0 \n" ); document.write( "factor by grouping \n" ); document.write( "(2x^3 - 8x)+ (3x^2 - 12) = 0 \n" ); document.write( "2x(x^2-4)+3(x^2-4)=0 \n" ); document.write( "factor out common term \n" ); document.write( "(x^2-4)(2x+3)=0 \n" ); document.write( "solve for x \n" ); document.write( "x^2-4=0 \n" ); document.write( "x^2=4 \n" ); document.write( "x=±√4=±2 \n" ); document.write( "or \n" ); document.write( "2x+3=0 \n" ); document.write( "2x=-3 \n" ); document.write( "x=-3/2 \n" ); document.write( "x=-2, -3/2, 2 \n" ); document.write( ".. \n" ); document.write( "(x/(x+2) + (1/4) = 5 \n" ); document.write( "add(-1/4) to each side \n" ); document.write( "(x/(x+2) = 20/4-1/4=19/4 \n" ); document.write( "(x/(x+2)=19/4 \n" ); document.write( "cross-multiply \n" ); document.write( "4x=19(x+2)=19x+38 \n" ); document.write( "15x=-38 \n" ); document.write( "x=-38/15 \n" ); document.write( "x≈2.5333.. \n" ); document.write( ".. \n" ); document.write( "x^(5/4) - 32 = 0 \n" ); document.write( "x^(5/4) = 32 \n" ); document.write( "raise both sides to the 4/5 power \n" ); document.write( "x=32^(4/5)=16 (take fifth root of 32=2, then raise it to the 4th power=2^4=16 \n" ); document.write( ".. \n" ); document.write( "(6x^4) - (23x^2) + 20 = 0 \n" ); document.write( "6x^4-23x^2+20 = 0 \n" ); document.write( "let u=x^2 \n" ); document.write( "u^2=x^4 \n" ); document.write( "equation: \n" ); document.write( "6u^2-23u+20=0 \n" ); document.write( "solve for u, using following quadratic formula: \n" ); document.write( " \n" ); document.write( "a=6, b=-23, c=20 \n" ); document.write( "ans: \n" ); document.write( "u=2.5 \n" ); document.write( "or \n" ); document.write( "u=4/3 \n" ); document.write( "solve for x: \n" ); document.write( "x^2=u=2.5 \n" ); document.write( "x=±√2.5 \n" ); document.write( "or \n" ); document.write( "x^2=4/3 \n" ); document.write( "x=±√(4/3) \n" ); document.write( ".. \n" ); document.write( "x=-√(4/3), -√(2.5), √2.5, and √(4/3) \n" ); document.write( " |