document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=634737>Question 634737</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Geometry. A square's side is increased by 9 yards, which corresponds to an increase in the area by 261 square yards. How many yards is the side of the initial square?\r<BR>\n" );
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document.write( "The sides of the square were ______ yards to begin with. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #399867 by </B><A HREF=/tutors/aboutme.mpl?userid=patrickca><B>patrickca(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=patrickca><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=399867\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of square = s * s or s^2\r<BR>\n" );
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document.write( "Area of rectangle after increase = (s + 9)(s + 9) or s^2 + 18s + 81\r<BR>\n" );
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document.write( "SO...\r<BR>\n" );
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document.write( "s^2 + 261 = s^2 + 18s + 81\r<BR>\n" );
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document.write( "261 = 18s + 81\r<BR>\n" );
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document.write( "180 = 18s\r<BR>\n" );
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document.write( "10 = s </SPAN>\n" );
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