document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=634686>Question 634686</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi could you please guide me through this? Thank you so much, and for your time!\r<BR>\n" );
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document.write( "Given a sequence is arithmetic find the 4 terms between 6 and 121.\r<BR>\n" );
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document.write( "Also: \r<BR>\n" );
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document.write( "Given the sequence is geometric find the 3 terms between 6 and 3.9366. \r<BR>\n" );
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document.write( "Thank you so much with these problems! Thank you a lot! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #399819 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=399819\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> # 1\r<BR>\n" );
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document.write( "Let d = common difference\r<BR>\n" );
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document.write( "So \r<BR>\n" );
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document.write( "6+d is the next term (after 6)\r<BR>\n" );
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document.write( "6+d+d = 6+2d is the next term (after the previous term above)\r<BR>\n" );
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document.write( "6+d+d+d = 6+3d is the next term (after the previous term above)\r<BR>\n" );
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document.write( "6+d+d+d+d = 6+4d is the next term (after the previous term above)\r<BR>\n" );
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document.write( "6+d+d+d+d+d = 6+5d is the next term (after the previous term above)\r<BR>\n" );
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document.write( "So we have the sequence...\r<BR>\n" );
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document.write( "6, 6+d, 6+2d, 6+3d, 6+4d, 6+5d\r<BR>\n" );
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document.write( "We have 6 terms and 4 terms are sandwiched between the terms \"6\" and \"6+5d\"\r<BR>\n" );
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document.write( "So the term 6+5d must be the term 121. So 6+5d = 121\r<BR>\n" );
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document.write( "Solve this for d. Then use this solution to find the missing 4 terms.\r<BR>\n" );
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document.write( "=======================================================\r<BR>\n" );
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document.write( "# 2\r<BR>\n" );
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document.write( "Let r = common ratio\r<BR>\n" );
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document.write( "So \r<BR>\n" );
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document.write( "We start off with 6\r<BR>\n" );
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document.write( "Then we move to 6*r or 6r to get the next term\r<BR>\n" );
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document.write( "Then we multiply by r again to get 6r^2 as the next term\r<BR>\n" );
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document.write( "Then we repeat to get 6r^3\r<BR>\n" );
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document.write( "Repeat again to get 6r^4\r<BR>\n" );
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document.write( "So we have the 5 terms\r<BR>\n" );
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document.write( "6, 6r, 6r^2, 6r^3, 6r^4\r<BR>\n" );
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document.write( "There are 3 terms in between the first term 6 and the last term 6r^4. The last term given to us is 3.9366\r<BR>\n" );
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document.write( "So \r<BR>\n" );
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document.write( "6r^4 = 3.9366\r<BR>\n" );
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document.write( "Solve this equation for r. Then use it to find the missing terms.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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