document.write( "Question 634662: Find the equations of the asymptotes.\r
\n" );
document.write( "\n" );
document.write( "y^2-9x^2-12y-36x-9=0 \n" );
document.write( "
Algebra.Com's Answer #399804 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the equations of the asymptotes. \n" ); document.write( "y^2-9x^2-12y-36x-9=0 \n" ); document.write( "complete the squares \n" ); document.write( "y^2-12y-9x^2-36x-9=0 \n" ); document.write( "(y^2-12y+36)-9(x^2+4x+4)=9+36-36 \n" ); document.write( "(y-6)^2-9(x+2)^2=9 \n" ); document.write( " \n" ); document.write( "This is an equation of a hyperbola with vertical transverse axis: \n" ); document.write( "Its standard form: \n" ); document.write( ".. \n" ); document.write( "asymptotes are straight lines that intersect at the center. \n" ); document.write( "form of equation: y=mx+b, m=slope, b=y-intercept \n" ); document.write( "slopes of asymptotes of hyperbolas with vertical transverse axis: ±a/b \n" ); document.write( "For given hyperbola: \n" ); document.write( "center: (-2,6) \n" ); document.write( "a^2=9 \n" ); document.write( "a=3 \n" ); document.write( "b^2=1 \n" ); document.write( "b=1 \n" ); document.write( "slope,m=±a/b=±3/1=±3 \n" ); document.write( ".. \n" ); document.write( "equation of asymptote with slope=-3 \n" ); document.write( "y=mx+b \n" ); document.write( "y=-3x+b \n" ); document.write( "solve for b using coordinates of center \n" ); document.write( "6=-3*-2+b \n" ); document.write( "b=0 \n" ); document.write( "equation: y=-3x \n" ); document.write( ".. \n" ); document.write( "equation of asymptote with slope=3 \n" ); document.write( "y=mx+b \n" ); document.write( "y=3x+b \n" ); document.write( "solve for b using coordinates of center \n" ); document.write( "6=3*-2+b \n" ); document.write( "b=12 \n" ); document.write( "equation: y=3x+12 \n" ); document.write( ".. \n" ); document.write( "equations of asymptotes: y=-3x and y=3x+12 \n" ); document.write( " \n" ); document.write( " |