document.write( "Question 634662: Find the equations of the asymptotes.\r
\n" ); document.write( "\n" ); document.write( "y^2-9x^2-12y-36x-9=0
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Algebra.Com's Answer #399804 by lwsshak3(11628)\"\" \"About 
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Find the equations of the asymptotes.
\n" ); document.write( "y^2-9x^2-12y-36x-9=0
\n" ); document.write( "complete the squares
\n" ); document.write( "y^2-12y-9x^2-36x-9=0
\n" ); document.write( "(y^2-12y+36)-9(x^2+4x+4)=9+36-36
\n" ); document.write( "(y-6)^2-9(x+2)^2=9
\n" ); document.write( "\"%28y-6%29%5E2%2F9-%28x%2B2%29%5E2%2F1=1\"
\n" ); document.write( "This is an equation of a hyperbola with vertical transverse axis:
\n" ); document.write( "Its standard form: \"%28y-k%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2=1\", (h,k)=(x,y) coordinates of center
\n" ); document.write( "..
\n" ); document.write( "asymptotes are straight lines that intersect at the center.
\n" ); document.write( "form of equation: y=mx+b, m=slope, b=y-intercept
\n" ); document.write( "slopes of asymptotes of hyperbolas with vertical transverse axis: ±a/b
\n" ); document.write( "For given hyperbola: \"%28y-6%29%5E2%2F9-%28x%2B2%29%5E2%2F1=1\"
\n" ); document.write( "center: (-2,6)
\n" ); document.write( "a^2=9
\n" ); document.write( "a=3
\n" ); document.write( "b^2=1
\n" ); document.write( "b=1
\n" ); document.write( "slope,m=±a/b=±3/1=±3
\n" ); document.write( "..
\n" ); document.write( "equation of asymptote with slope=-3
\n" ); document.write( "y=mx+b
\n" ); document.write( "y=-3x+b
\n" ); document.write( "solve for b using coordinates of center
\n" ); document.write( "6=-3*-2+b
\n" ); document.write( "b=0
\n" ); document.write( "equation: y=-3x
\n" ); document.write( "..
\n" ); document.write( "equation of asymptote with slope=3
\n" ); document.write( "y=mx+b
\n" ); document.write( "y=3x+b
\n" ); document.write( "solve for b using coordinates of center
\n" ); document.write( "6=3*-2+b
\n" ); document.write( "b=12
\n" ); document.write( "equation: y=3x+12
\n" ); document.write( "..
\n" ); document.write( "equations of asymptotes: y=-3x and y=3x+12
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