document.write( "Question 634656: I think this is a graphing question:\r
\n" ); document.write( "\n" ); document.write( "Find the coordinates of the vertex for the parabola f(x)=-2x^2-2x.
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Algebra.Com's Answer #399770 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,\r
\n" ); document.write( "\n" ); document.write( "Find the coordinates of the vertex for the parabola
\n" ); document.write( "f(x)= -2x^2-2x.
\n" ); document.write( "| completing the Square to find the Vertex: y = ax^2 + bx + c ⇒ y = a(x -(-b/2a)^2) - a(-b/2a)^2 + c
\n" ); document.write( "f(x) = -2(x+1/2)^2 + 1/2 V(-1/2,1/2)
\n" ); document.write( "the vertex form of a Parabola opening up(a>0) or down(a<0)is: \"y=a%28x-h%29%5E2+%2Bk\"
\n" ); document.write( "where(h,k) is the vertex
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