document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=633590>Question 633590</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (X-2)/(x+1)-(3-12x)/(2x^2-x-3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #399759 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=399759\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> as2x^2-x-3=2x^2+2x-3x-3=2x(x+1)-3(x+1)=(x+1)(2x-3)\r<BR>\n" );
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document.write( "now (X-2)/(x+1)-(3-12x)/(2x^2-x-3)=(x-2)/(x+1)-(3-12x)/(x+1)(2x-3)<BR>\n" );
document.write( "=[(x-2)(2x-3)-(3-12x)]/(x+1)(2x-3)<BR>\n" );
document.write( "=[2x^2-3x-4x+6-3+12x]/(x+1)(2x-3)<BR>\n" );
document.write( "=[2x^2+5x+3]/(x+1)(2x-3)<BR>\n" );
document.write( "=[2x^2+2x+3x+3]/(x+1)(2x-3)<BR>\n" );
document.write( "=[2x(x+1)+3(x+1)]/(x+1)(2x-3)<BR>\n" );
document.write( "=(x+1)(2x+3)/(x+1)(2x-3)<BR>\n" );
document.write( "=(2x+3)/(2x-3) ans </SPAN>\n" );
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