document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=633587>Question 633587</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Subtract<BR>\n" );
document.write( "(2x-7)/(x^2-64)-(3x-15)/(x^2-64) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #399757 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=399757\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Subtract<BR>\n" );
document.write( "(2x-7)/(x^2-64)-(3x-15)/(x^2-64)=[(2x-7)-(3x-15)]/(x^2-64)=(2x-7-3x+15)/(x^2-64)<BR>\n" );
document.write( "=(-x+8)/(x^2-64)=-(x-8)/(x+8)(x-8)=-1/(x+8) ans </SPAN>\n" );
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