document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=634610>Question 634610</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determine algebraically whether f(x)=x^3-x^2+1 is odd,even,neither.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #399755 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=399755\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Determine algebraically whether f(x)=x^3-x^2+1 is odd,even,neither.\r<BR>\n" );
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document.write( "ans:-<BR>\n" );
document.write( "if f(x)=f(-x) then the function is even<BR>\n" );
document.write( "if -f(x)=f(-x) then the function is odd<BR>\n" );
document.write( "so f(-x)=(-x)^3-(-x)^2+1=-x^3-x^2+1=-(x^3+x^2-1)=/-f(x)<BR>\n" );
document.write( "so the function is neither even nor odd ans<BR>\n" );
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