document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=634557>Question 634557</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Helloooo~ Can you help me with these problem? :)\r<BR>\n" );
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document.write( "How many ounces of pure silver should be added to 180 ounces, 75% pure, to obtain a mixture of 80% pure?\r<BR>\n" );
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document.write( "Thaaaank yoou in advance. Good day! :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #399699 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=399699\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amt of pure silver needed<BR>\n" );
document.write( "Now we know that the amount of PURE silver that exists before the mixture takes place has to equal the amount of PURE silver that exists after the mixture takes place:\r<BR>\n" );
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document.write( "Pure silver before the mixture takes place: x+180*0.75=x+135<BR>\n" );
document.write( "Pure silver after the mixture takes place: (180+x)*0.80=144+0.80x\r<BR>\n" );
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document.write( "Sooooooooooooo:<BR>\n" );
document.write( "x+135=0.80x+144 subtract 0.80x and also 135 from both sides<BR>\n" );
document.write( "x-0.80x+135-135=0.80x-0.80x+144-135 collect like terms<BR>\n" );
document.write( "0.20x=9<BR>\n" );
document.write( "x=45 oz-----------------amt of pure silver needed<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "45+135=144+0.80*45<BR>\n" );
document.write( "180=180\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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