document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=634502>Question 634502</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If two percent of electric bulbs manufactured are defective,find the probability that in a sample of 200 bulbs less than 2 bulbs are defective.<BR>\n" );
document.write( "[Given: e to the power of -4 =0.0183,e to the power -2=0.114] </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #399674 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=399674\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If two percent of electric bulbs manufactured are defective,find the probability that in a sample of 200 bulbs less than 2 bulbs are defective.<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "Binomial Problem with n = 200 and p(defect) = 0.02<BR>\n" );
document.write( "P(0<= x <=1) = P(x = 0) + P(x = 1)<BR>\n" );
document.write( "= 200C0*0.02^0*0.98^200 + 200C1*0.02*0.98^199 = 1*1*0.01759 + 200*0.02*0.0179<BR>\n" );
document.write( "= 0.01759 + 0.0718 = 0.064<BR>\n" );
document.write( "---<BR>\n" );
document.write( "OR, using a TI-84 calculator, you would get:<BR>\n" );
document.write( "P(0<= x <=1) = binomcdf(200,0.02,1) = 0.0894<BR>\n" );
document.write( "==================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================= </SPAN>\n" );
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