document.write( "Question 634159: An employee at See's Candy Store needs a special mixture of candy. She has creme-filled chocolates that sell for $3.00 per pound, chocolate-covered nuts that sell for $2.70 per pound, and chocolate-covered raisins that sell for $2.25 per pound. She wants to have twice as many raisins as nuts in the mixture. Find how many pounds of each she should use to make 45 pounds worth $2.80 per pound.
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\n" ); document.write( "\n" ); document.write( "Here's how I set up the problem:\r
\n" ); document.write( "\n" ); document.write( "a + b + c = 45
\n" ); document.write( "3a + 2.7b + 2.25c = 2.8(45)\r
\n" ); document.write( "\n" ); document.write( "Eventually, I ended up with no solution, which I am pretty certain isn't the correct answer. My textbook does not have any example problems of this nature, so I don't really have any idea as to how to go about solving them; any help would be greatly appreciated.
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Algebra.Com's Answer #399662 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
you have three unknowns
\n" ); document.write( "you need at least three equations
\n" ); document.write( "c for creme
\n" ); document.write( "n for nuts
\n" ); document.write( "r for raisins
\n" ); document.write( "c+n+r=45
\n" ); document.write( "3c + 2.7n + 2.25r= 2.8(45)
\n" ); document.write( "Now you need a third equation.
\n" ); document.write( "r=2n
\n" ); document.write( "c=30., n=5., r=10.
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