document.write( "Question 634159: An employee at See's Candy Store needs a special mixture of candy. She has creme-filled chocolates that sell for $3.00 per pound, chocolate-covered nuts that sell for $2.70 per pound, and chocolate-covered raisins that sell for $2.25 per pound. She wants to have twice as many raisins as nuts in the mixture. Find how many pounds of each she should use to make 45 pounds worth $2.80 per pound.
\n" );
document.write( "--------------------------------------------------\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "Here's how I set up the problem:\r
\n" );
document.write( "\n" );
document.write( "a + b + c = 45
\n" );
document.write( "3a + 2.7b + 2.25c = 2.8(45)\r
\n" );
document.write( "\n" );
document.write( "Eventually, I ended up with no solution, which I am pretty certain isn't the correct answer. My textbook does not have any example problems of this nature, so I don't really have any idea as to how to go about solving them; any help would be greatly appreciated. \n" );
document.write( "
Algebra.Com's Answer #399662 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! you have three unknowns \n" ); document.write( "you need at least three equations \n" ); document.write( "c for creme \n" ); document.write( "n for nuts \n" ); document.write( "r for raisins \n" ); document.write( "c+n+r=45 \n" ); document.write( "3c + 2.7n + 2.25r= 2.8(45) \n" ); document.write( "Now you need a third equation. \n" ); document.write( "r=2n \n" ); document.write( "c=30., n=5., r=10. \n" ); document.write( " |