document.write( "Question 634449: I am a little confused on how to solve this. I need to solve and give exact and approximate solution to three decimal places. Any help, showing steps, would be really appreciated so I can understand how to do this type of problem. THanks.\r
\n" ); document.write( "\n" ); document.write( "y^2-18y+81=25 \n" ); document.write( "

Algebra.Com's Answer #399653 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+y%5E2+-+18y+%2B+81+=+25+\"$
\n" ); document.write( " $\"+y%5E2+-+18y+=+-56+\"$
\n" ); document.write( "Complete the square
\n" ); document.write( " $\"+y%5E2+-+18y+%2B+%2818%2F2%29%5E2+=+-56+%2B+%2818%2F2%29%5E2+\"$
\n" ); document.write( " $\"+y%5E2+-+18y+%2B+81+=+-56+%2B+81+\"$
\n" ); document.write( "This ends up being what I started with,
\n" ); document.write( "since I didn't realize both sides were
\n" ); document.write( "perfect squares, but now I've proven it
\n" ); document.write( " $\"+%28+y+-+9+%29%5E2++=+5%5E2+\"$
\n" ); document.write( "Take the square root of both sides
\n" ); document.write( " $\"+y+-+9+=+5+\"$
\n" ); document.write( " $\"+y+=+14+\"$
\n" ); document.write( "and taking negative square root of $\"+5%5E2+\"$
\n" ); document.write( " $\"+y+-+9+=+-5+\"$
\n" ); document.write( " $\"+y+=+4+\"$
\n" ); document.write( "I can check by plugging both results back into equation
\n" ); document.write( " $\"+y%5E2+-+18y+%2B+81+=+25+\"$
\n" ); document.write( " $\"+14%5E2+-+18%2A14+%2B+81+=+25+\"$
\n" ); document.write( " $\"+196+-+252+%2B+81+=+25+\"$
\n" ); document.write( " $\"+25+=+25+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+4%5E2+-+18%2A4+%2B+81+=+25+\"$
\n" ); document.write( " $\"+16+-+72+%2B+81+=+25+\"$
\n" ); document.write( " $\"+25+=+25+\"$
\n" ); document.write( "OK \n" ); document.write( "

\n" );