document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=634449>Question 634449</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am a little confused on how to solve this.  I need to solve  and give exact and approximate solution to three decimal places.  Any help, showing steps, would be really appreciated so I can understand how to do this type of problem.  THanks.\r<BR>\n" );
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document.write( "y^2-18y+81=25 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #399632 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=399632\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y^2 - 18y + 81 = 25<BR>\n" );
document.write( "subtract 25 from both sides and solve it as a quadratic equation<BR>\n" );
document.write( "y^2 - 18y + 81 - 25 = 0<BR>\n" );
document.write( "y^2 - 18y + 56 = 0<BR>\n" );
document.write( "You can use the quadratic formula, but this will factor to<BR>\n" );
document.write( "(y-4)(y-14) = 0<BR>\n" );
document.write( "Two solutions which are integers<BR>\n" );
document.write( "y = 4<BR>\n" );
document.write( "and<BR>\n" );
document.write( "y = 14 </SPAN>\n" );
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