document.write( "Question 634415: The length of a rectangle is 2 in. less than four times the width. If the diagnol is 4 in. more than the length, find the dimensions of the rectangle.\r
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document.write( "The width of the rectangle is ?
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document.write( "The length of the rectangle is ? \n" );
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Algebra.Com's Answer #399594 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangle is 2 in. less than four times the width. If the diagnol is 4 in. more than the length, find the dimensions of the rectangle. \n" ); document.write( "The width of the rectangle is ? \n" ); document.write( "The length of the rectangle is ? \n" ); document.write( "** \n" ); document.write( "let w=width \n" ); document.write( "4w-2=length \n" ); document.write( "length of diagonal=4w-2+4=4w+2 \n" ); document.write( "by pythagorean theorem: \n" ); document.write( "diagonal^2=width^2+length^2 \n" ); document.write( "(4w+2)^2=w^2+(4w-2)^2 \n" ); document.write( "16w^2+16w+4=w^2+16w^2-16w+4 \n" ); document.write( "w^2-32w=0 \n" ); document.write( "w(w-32)=0 \n" ); document.write( "w=0 (reject, w>0) \n" ); document.write( "or \n" ); document.write( "w=32 \n" ); document.write( "4w-2=128-2=126 \n" ); document.write( "4w+2=128+2=130 \n" ); document.write( ".. \n" ); document.write( "width of the rectangle is=32 in \n" ); document.write( "length of the rectangle is=126 in \n" ); document.write( "length of diagonal=130 in \n" ); document.write( " \n" ); document.write( " |