document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=634412>Question 634412</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello. I got these questions and I really could use some help.<BR>\n" );
document.write( "1. 6e^(1-x)+1 = 21<BR>\n" );
document.write( "2. 4x + 2e^(2y) -8 = 0.\r<BR>\n" );
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document.write( "Withe the first one, I got as far as the fraction:<BR>\n" );
document.write( "lne^(1-x) = ln 20/6<BR>\n" );
document.write( "Please help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #399575 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=399575\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. 6e^(1-x)+1 = 21<BR>\n" );
document.write( "e^(1-x) = 20/6 = 10/3<BR>\n" );
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document.write( "ln(e^xyz) = xyz<BR>\n" );
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document.write( "1-x = ln(10/3)<BR>\n" );
document.write( "x = 1 - ln(10/3)<BR>\n" );
document.write( "x =~ -0.2039728<BR>\n" );
document.write( "===================<BR>\n" );
document.write( "2. 4x + 2e^(2y) -8 = 0<BR>\n" );
document.write( "What do you want to do with this one?<BR>\n" );
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