document.write( "Question 58276: I need help in this Q plz
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document.write( "10) The letters of word ALGEBRA
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document.write( "a- How many diffrent ways the letters can be arranged in a row ?
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document.write( "b- In how many ways of these arrangments the two A's are together?
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document.write( "c- In how many ways of these arrangments the two A's are not together? \n" );
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Algebra.Com's Answer #39954 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! I'll take a stab at it- I could be wrong, though \n" ); document.write( "Suppose ALGEBRA didn't have 2 A's? \n" ); document.write( "Suppose it was ALGEBRX instead \n" ); document.write( "Then I could pick 7 different letters for the first letter \n" ); document.write( "I'd have 6 different letters to choose from for the 2nd letter \n" ); document.write( "I'd have 5 different letters to choose from for the 3rd letter \n" ); document.write( "etc. \n" ); document.write( "The number of combinations would be \n" ); document.write( "7 * 6 * 5 * 4 * 3 * 2 * 1 = 5040 \n" ); document.write( "but X and A are treated differently \n" ); document.write( "A . . . . .X \n" ); document.write( "X . . . . .A \n" ); document.write( "and \n" ); document.write( ".A . . . . .X \n" ); document.write( ".X . . . . .A \n" ); document.write( "All these paired A's and X's should be treated as a single A . . . . .A pair \n" ); document.write( "so, divide 5040 by 2. \n" ); document.write( "5040 / 2 = 2520 possible words from ALGEBRA \n" ); document.write( "The double AA can be 1st , second, third, etc \n" ); document.write( "AA . . . . . \n" ); document.write( " . AA . . . . \n" ); document.write( " . . AA . . . \n" ); document.write( " . . . AA . . \n" ); document.write( " . . . . AA . \n" ); document.write( " . . . . . AA \n" ); document.write( "That's 6 different ways AA can appear \n" ); document.write( "The words without the AA is simply 2520 - 6 = 2514 \n" ); document.write( " |