document.write( "Question 634341: Find the standard score (z) such that the area above the mean and below z is about 34% of the area under the normal curve. \n" ); document.write( "
Algebra.Com's Answer #399524 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi,
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document.write( "Find the standard score (z) such that the area above the mean and below z is 
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document.write( "about 34% of the area under the normal curve.  \"z+=+1\"\r
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document.write( "For the normal distribution: 
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document.write( " one  standard deviation  from the mean accounts for about 68.2% of the set 
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document.write( "two standard deviations from the mean account for about 95.4%
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document.write( "and three standard deviations from the mean account for about 99.7%.
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document.write( "Important to Understand z -values as they relate to the Standard Normal curve:
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document.write( "Below:  z = 0, z = ± 1, z= ±2 , z= ±3 are plotted.  
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document.write( "Note: z = 0 (x value the mean) 50% of the area under the curve is to the left and 50%  to the right
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