document.write( "Question 634327: please help.\r
\n" ); document.write( "\n" ); document.write( "question: consider the parabola ( i know that on a graph thats the if you say smiley face on a graph) with the equation y+5=2(x+2)^2.
\n" ); document.write( "a. What is the vertex?
\n" ); document.write( "(i thought the vertex was the (x+2) but im completely not sure)
\n" ); document.write( "b. what are its x-intercepts?
\n" ); document.write( "(i was lost after that to find the x-intercept wouldnt i have to take everything from the right expect the x to find the intercept) please help me their is a third question but i know it says no graphs so i will not include c.) \n" ); document.write( "
Algebra.Com's Answer #399515 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
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document.write( "Hi,
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document.write( "y+5=2(x+2)^2  (y = 0 ⇒  (x+2)^2 = 5/2 and x-intercepts are: -2 ± \"sqrt%285%2F2%29\"
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document.write( "y  =2(x+2)^2 - 5 ,              V(-2,-5)
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document.write( "the vertex form of a Parabola opening up(a>0) or down(a<0)is: \"y=a%28x-h%29%5E2+%2Bk\" 
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document.write( "where is the vertex  and  x = h  is the Line of Symmetry
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