document.write( "Question 634305: Given three consecutive odd numbers such that the square of the second number is 192 less than the square of the third. Find those numbers. \n" ); document.write( "

Algebra.Com's Answer #399505 by graphmatics(170) $\"\"$ $\"About$

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Let 2n+1 be the first odd integer, then 2n+3 and 2n+5 are the second and third consecutive odd integers
\n" ); document.write( " $\"%282n%2B3%29%5E2%2B192=%282n%2B5%29%5E2\"$
\n" ); document.write( " $\"4%2An%5E2%2B12%2An%2B9%2B192=4%2An%5E2%2B20%2An%2B25\"$
\n" ); document.write( " $\"12%2An-20%2An=25-201\"$
\n" ); document.write( " $\"-8%2An=-176\"$
\n" ); document.write( " $\"n=22\"$
\n" ); document.write( "The consecutive odd integers are 45,47 and 49. \n" ); document.write( "

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