document.write( "Question 634295: How to solve this?\r
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document.write( "Chris is 3 years older than Beth. Seven years from now she will be twice as old as Beth was a year ago. How old is each now? \n" );
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Algebra.Com's Answer #399498 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Chris is 3 years older than Beth. Seven years from now she will be twice as old as Beth was a year ago. How old is each now? \n" ); document.write( "let x=Beth's age now \n" ); document.write( "x+3=Chris' age now \n" ); document.write( "7 years from now: \n" ); document.write( "Chris' age=x+3+7=x+10 \n" ); document.write( "A year ago: \n" ); document.write( "Beth's age=x-1 \n" ); document.write( ".. \n" ); document.write( "Seven years from now Chris will be twice as old as Beth was a year ago. \n" ); document.write( "x+10=2(x-1) \n" ); document.write( "x+10=2x-2 \n" ); document.write( "x=12 \n" ); document.write( "x+3=15 \n" ); document.write( "Beth's age now=12 \n" ); document.write( "Chris' age now=15 \n" ); document.write( " |