document.write( "Question 634295: How to solve this?\r
\n" ); document.write( "\n" ); document.write( "Chris is 3 years older than Beth. Seven years from now she will be twice as old as Beth was a year ago. How old is each now?
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Algebra.Com's Answer #399498 by lwsshak3(11628)\"\" \"About 
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Chris is 3 years older than Beth. Seven years from now she will be twice as old as Beth was a year ago. How old is each now?
\n" ); document.write( "let x=Beth's age now
\n" ); document.write( "x+3=Chris' age now
\n" ); document.write( "7 years from now:
\n" ); document.write( "Chris' age=x+3+7=x+10
\n" ); document.write( "A year ago:
\n" ); document.write( "Beth's age=x-1
\n" ); document.write( "..
\n" ); document.write( "Seven years from now Chris will be twice as old as Beth was a year ago.
\n" ); document.write( "x+10=2(x-1)
\n" ); document.write( "x+10=2x-2
\n" ); document.write( "x=12
\n" ); document.write( "x+3=15
\n" ); document.write( "Beth's age now=12
\n" ); document.write( "Chris' age now=15
\n" ); document.write( "
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