document.write( "Question 634193: The following table shows the Myers-Briggs personality preferences for a random sample of 406 people in the listed professions. E refers to extroverted and I refers to introverted. \r
\n" ); document.write( "\n" ); document.write( " Personality Type
\n" ); document.write( " Occupation EI Row Total
\n" ); document.write( "Clergy (all denominations) 67 40 107
\n" ); document.write( "M.D. 67 95 162
\n" ); document.write( "Lawyer 56 81 137
\n" ); document.write( "Column Total 190 216 406\r
\n" ); document.write( "\n" ); document.write( "Use the chi-square test to determine if the listed occupations and personality preferences are independent at the 0.05 level of significance.\r
\n" ); document.write( "\n" ); document.write( "(a) What is the level of significance? = ________\r
\n" ); document.write( "\n" ); document.write( "(b) Find the value of the chi-square statistic for the sample. (Round the expected frequencies to at least three decimal places. Round the test statistic to three decimal places.) = ________\r
\n" ); document.write( "\n" ); document.write( "What are the degrees of freedom?\r
\n" ); document.write( "\n" ); document.write( "(c) Find or estimate the P-value of the sample test statistic. (Round your answer to three decimal places.)\r
\n" ); document.write( "\n" ); document.write( "
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Algebra.Com's Answer #399435 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The following table shows the Myers-Briggs personality preferences for a random sample of 406 people in the listed professions. E refers to extroverted and I refers to introverted. \r
\n" ); document.write( "\n" ); document.write( " Personality Type
\n" ); document.write( " Occupation E I Row Total
\n" ); document.write( "Clergy (all denominations) 67 40 107
\n" ); document.write( "M.D. 67 95 162
\n" ); document.write( "Lawyer 56 81 137
\n" ); document.write( "Column Total 190 216 406\r
\n" ); document.write( "\n" ); document.write( "Use the chi-square test to determine if the listed occupations and personality preferences are independent at the 0.05 level of significance.\r
\n" ); document.write( "\n" ); document.write( "(a) What is the level of significance? = 5%
\n" ); document.write( "Find the value of the chi-square statistic for the sample. (Round the expected frequencies to at least three decimal places. Round the test statistic to three decimal places. ChiSq = 14.610
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\n" ); document.write( "\n" ); document.write( "What are the degrees of freedom?
\n" ); document.write( "Ans: 2
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\n" ); document.write( "\n" ); document.write( "(c) Find or estimate the P-value of the sample test statistic. (Round your answer to three decimal places.)
\n" ); document.write( "Ans: 0.000672
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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