document.write( "Question 58317: Prove that the diagonals of a parallelogram bisect each other. \n" ); document.write( "

Algebra.Com's Answer #39941 by Nate(3500) $\"\"$ $\"About$

You can put this solution on YOUR website!
Just graph a square on a cartesian coordinate plain.
\n" ); document.write( "P(1,1), N(-1,1), S(-1,-1), and M(1,-1)
\n" ); document.write( "The points that make the diagonals: (-1,1) and (1,-1) <~> (1,1) and (-1,-1)
\n" ); document.write( "Slope of (-1,1) and (1,-1)
\n" ); document.write( "m = (-1 - 1)/(1 + 1) = -2/2 = -1
\n" ); document.write( "Slope of (1,1) and (-1,-1)
\n" ); document.write( "m = (1 + 1)/(1 + 1) = 2/2 = 1
\n" ); document.write( "The slope of one is the inverse of it's negative counterpart. The lines are perpendicular. Now, you may have to put that in a proof; I do not if your school wants you to do so. \n" ); document.write( "

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