document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=634161>Question 634161</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ***Could someone explain to me how to solve these problems!  This is an online class and I am not getting much help from the Professor!\"  Thanks***\r<BR>\n" );
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document.write( "(1) A fair quarter is flipped three times. For each of the following probabilities, use the formula for the binomial distribution and a calculator to compute the requested probability. Next, look up the probability in the binomial probability distribution table. (Enter your answers to three decimal places.) <BR>\n" );
document.write( "(a) Find the probability of getting exactly three heads. = ________<BR>\n" );
document.write( "(b) Find the probability of getting exactly two heads. = ________<BR>\n" );
document.write( "(c) Find the probability of getting two or more heads. = ________<BR>\n" );
document.write( "(d) Find the probability of getting exactly three tails. = _______\r<BR>\n" );
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document.write( "(2) The one-time fling! Have you ever purchased an article of clothing (dress, sports jacket, etc.), worn the item once to a party, and then returned the purchase? This is called a one-time fling. About 20% of all adults deliberately do a one-time fling and feel no guilt about it! In a group of six adult friends, what is the probability of the following? (Round your answers to three decimal places.) <BR>\n" );
document.write( "(a) no one has done a one-time fling = ________<BR>\n" );
document.write( "(b) at least one person has done a one-time fling = ________<BR>\n" );
document.write( "(c) no more than two people have done a one-time fling = ________\r<BR>\n" );
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document.write( "(3) What percentage of the area under the normal curve lies between &#956; &#8722; &#963; and &#956; + &#963;?<BR>\n" );
document.write( "What percentage of the area under the normal curve lies between &#956; &#8722; 3&#963; and &#956; + 3&#963;?\r<BR>\n" );
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document.write( "(4) Sketch the area under the standard normal curve over the indicated interval and find the specified area. (Round your answer to four decimal places.) <BR>\n" );
document.write( "The area between z = &#8722;2.18and z = 1.37 is ________\r<BR>\n" );
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document.write( "(5) Let z be a random variable with a standard normal distribution. Find the indicated probability. (Round your answer to four decimal places.)<BR>\n" );
document.write( "P(&#8722;1.25 &#8804; z &#8804; 2.40) = ________\r<BR>\n" );
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document.write( "(6) Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.) <BR>\n" );
document.write( "&#956; = 4.4; &#963; = 2.3 <BR>\n" );
document.write( "P(3 &#8804; x &#8804; 6) = ________\r<BR>\n" );
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document.write( "(7) Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.) <BR>\n" );
document.write( "&#956; = 29; &#963; = 3.9 <BR>\n" );
document.write( "P(x &#8805; 30) = ________\r<BR>\n" );
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document.write( "(8) Find z such that 68% of the standard normal curve lies to the right of z. (Round your answer to two decimal places.)<BR>\n" );
document.write( "z = ________\r<BR>\n" );
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document.write( "(9) Total plasma volume is important in determining the required plasma component in blood replacement therapy for a person undergoing surgery. Plasma volume is influenced by the overall health and physical activity of an individual. Suppose that a random sample of 50 male firefighters are tested and that they have a plasma volume sample mean of x = 37.5 ml/kg (milliliters plasma per kilogram body weight). Assume that &#963; = 7.80 ml/kg for the distribution of blood plasma. <BR>\n" );
document.write( "(a) Find a 99% confidence interval for the population mean blood plasma volume in male firefighters. What is the margin of error? (Round your answers to two decimal places.) <BR>\n" );
document.write( "lower limit = ________<BR>\n" );
document.write( "upper limit = ________<BR>\n" );
document.write( "margin of error = ________\r<BR>\n" );
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document.write( "(10) For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.\r<BR>\n" );
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document.write( "A random sample of 5427 physicians in Colorado showed that 3062 provided at least some charity care (i.e., treated poor people at no cost). \r<BR>\n" );
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document.write( "(a) Let p represent the proportion of all Colorado physicians who provide some charity care. Find a point estimate for p. (Round your answer to four decimal places.) = 0.5642<BR>\n" );
document.write( "(b) Find a 99% confidence interval for p. (Round your answers to three decimal places.) <BR>\n" );
document.write( "lower limit = ________<BR>\n" );
document.write( "upper limit = ________<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #399395 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=399395\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">   <PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\"><font face = \"Tohoma\" size = 3 color = \"indigo\"><b> <BR>\n" );
document.write( "Hi,<BR>\n" );
document.write( "Oh dear...<BR>\n" );
document.write( "1) and 2) are ex of Biomonial Probability: P = nCx* <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p%5Ex%2Aq%5E%28n-x%29 ALIGN=MIDDLE  ALT=\"p%5Ex%2Aq%5E%28n-x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " p = 1/2  and q = 1/2 <BR>\n" );
document.write( "1a. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P%28x=3%29=+3C3%281%2F2%29%5E3=+1%2F8+ ALIGN=MIDDLE  ALT=\"P%28x=3%29=+3C3%281%2F2%29%5E3=+1%2F8+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "1b. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P%28x=2%29+=+3C2%281%2F2%29%5E2%281%2F2%29%5E1+=+3%2F8 ALIGN=MIDDLE  ALT=\"P%28x=2%29+=+3C2%281%2F2%29%5E2%281%2F2%29%5E1+=+3%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "1c. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P%28x=2%29+%2B+P%28x=3%29+=+1%2F2 ALIGN=MIDDLE  ALT=\"P%28x=2%29+%2B+P%28x=3%29+=+1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "1d. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P%28x=0%29+=+3C0q%5E3+=+1%2F8 ALIGN=MIDDLE  ALT=\"P%28x=0%29+=+3C0q%5E3+=+1%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "2a. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P%28x+=+0%29+=+q%5E3+=+6C0%28.8%29%5E3 ALIGN=MIDDLE  ALT=\"P%28x+=+0%29+=+q%5E3+=+6C0%28.8%29%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" >     p = .20  and q = .80<BR>\n" );
document.write( "2b. P(x&#8805; 1) = 1 - P(0)<BR>\n" );
document.write( "3b. P(no more than two) = 1- P(3) = 1 - (.20)^6<BR>\n" );
document.write( "As to 3 - 8, these are ex of normal distribution: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=z+=+%28x+-+mu%29%2F%28sigma%29 ALIGN=MIDDLE  ALT=\"z+=+%28x+-+mu%29%2F%28sigma%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "recommend finding P(z value) as needed using NORMSDIST Excel function <BR>\n" );
document.write( "For the normal distribution: <BR>\n" );
document.write( "one  standard deviation from the mean accounts for about 68.2% of the set <BR>\n" );
document.write( "two standard deviations from the mean account for about 95.4%<BR>\n" );
document.write( "and three standard deviations from the mean account for about 99.7%.<BR>\n" );
document.write( "Important to Understand z -values as they relate to the Standard Normal curve:<BR>\n" );
document.write( "Below:  z = 0, z = ± 1, z= ±2 , z= ±3 are plotted.  <BR>\n" );
document.write( "Note: z = 0 (x value the mean) 50% of the area under the curve is to the left and 50%  to the right<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28400%2C200%2C-5%2C5%2C-.5%2C1.5%2C+graph%28400%2C200%2C-5%2C5%2C-.5%2C1.5%2C+exp%28-x%5E2%2F2%29%29%2C+green%28line%281%2C0%2C1%2Cexp%28-1%5E2%2F2%29%29%2Cline%28-1%2C0%2C-1%2Cexp%28-1%5E2%2F2%29%29%29%2Cgreen%28line%282%2C0%2C2%2Cexp%28-2%5E2%2F2%29%29%2Cline%28-2%2C0%2C-2%2Cexp%28-2%5E2%2F2%29%29%29%2Cgreen%28line%283%2C0%2C3%2Cexp%28-3%5E2%2F2%29%29%2Cline%28-3%2C0%2C-3%2Cexp%28-3%5E2%2F2%29%29%29%2Cgreen%28line%28+0%2C0%2C+0%2Cexp%280%5E2%2F2%29%29%29%2Clocate%284.8%2C-.01%2Cz%29%2Clocate%284.8%2C.2%2Cz%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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