document.write( "Question 631713: please help me solve this mixture problem. Thanks! \r
\n" ); document.write( "\n" ); document.write( "Maricar has a solution that is 60% alcohol and another solution that is 60% alcohol. If maricar wants 12 gallons of a solution that is 45% alcohol, how many gallons of the 40% solution and of the 60% solution should be mix together to obtain her 45% solution?
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Algebra.Com's Answer #399314 by Maths68(1474)\"\" \"About 
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Solution A
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\n" ); document.write( "Amount = x
\n" ); document.write( "Concentration =40% =0.4\r
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\n" ); document.write( "\n" ); document.write( "Solution B
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\n" ); document.write( "Amount = 12-x
\n" ); document.write( "Concentration =60% = 0.6\r
\n" ); document.write( "\n" ); document.write( "Mixture
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\n" ); document.write( "Amount =12
\n" ); document.write( "Concentration =45%=0.45\r
\n" ); document.write( "\n" ); document.write( "[Amount Solution A * Concentration A] + [Amount Solution B * Concentration of B] = [Amount of Mixture *Concentration of Mixture]
\n" ); document.write( "(x)(0.4)+(12-x)(0.6)=(12)(0.45)
\n" ); document.write( "0.4x+7.2-0.6x=5.4
\n" ); document.write( "-0.2x+7.2=5.4
\n" ); document.write( "-0.2x=-1.8
\n" ); document.write( "-0.2x/-0.2=-1.8/-0.2
\n" ); document.write( "x=9\r
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\n" ); document.write( "\n" ); document.write( "Solution A
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\n" ); document.write( "Amount = x = 9 gallons
\n" ); document.write( "Concentration =40% =0.4
\n" ); document.write( "Solution B
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\n" ); document.write( "Amount = 12-x = 12-9 = 3 gallons
\n" ); document.write( "Concentration =60% = 0.6\r
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\n" ); document.write( "\n" ); document.write( "9 gallons of the 40% solution and 3 gallons of the 60% solution should be mix together to obtain 12 gallons of 45% solution?\r
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