document.write( "Question 633882: The domain of the function f is {x: -1 < x < 5}. If g(x) = 2f(-x), what is the domain of the function g?\r
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\n" ); document.write( "\n" ); document.write( "i know that the answer is (-5 < x < 1) but I am curious about the steps necessary to get that answer
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Algebra.Com's Answer #399313 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
For x such that \"-5%3Cx%3C1\", then \"5%3E-x%3E-1\", which is the same as \"-1%3C-x%3C5\", so (-x) is in the domain of f(x).
\n" ); document.write( "Therefore, f(-x) is defined, and can be calculated and multiplied times 2 to find g(x).
\n" ); document.write( "For example, \"g%28-4%29=2%2Af%284%29\" exists, and so does \"g%280.7%29=2%2Af%28-0.7%29\".
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\n" ); document.write( "On the other hand, when \"x%3C=-5\", then \"-x%3E=5\",and
\n" ); document.write( "(-x) is out of the domain of f(x).
\n" ); document.write( "For \"x%3E=1\", \"-x%3C=-1\" is outside the domain of f(x).
\n" ); document.write( "In either case case f(-x) does not exist, and neither does g(x).
\n" ); document.write( "For example for x=-5, \"g%28-5%29=2%2Af%285%29\" does not exist. It is not defined.
\n" ); document.write( "The same goes for x=1. In that case, \"g%281%29=2%2Af%28-1%29\" does not exist either.
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\n" ); document.write( "The function f(x) could be simply defined as f(x)=8 for x such that -1\n" ); document.write( "If you like a fancier function, an example could be
\n" ); document.write( "\"f%28x%29=1%2Fsqrt%28%28x%2B1%29%285-x%29%29\"
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