document.write( "Question 633964: write a quadratic equation with integral coefficients given the following number as roots. 6, -2/3 \n" ); document.write( "

Algebra.Com's Answer #399307 by mananth(16946) $\"\"$ $\"About$

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6 & -2/3 are the roots of the equation\r
\n" ); document.write( "\n" ); document.write( "Let the roots be $\"alpha\"$ & $\"beta\"$ \r
\n" ); document.write( "\n" ); document.write( "in the general equation $\"ax%5E2%2Bbx%2Bc=0+\"$ \r
\n" ); document.write( "\n" ); document.write( "sum of the roots = -16/3 = -b/a\r
\n" ); document.write( "\n" ); document.write( "product of roots = -4 c/a\r
\n" ); document.write( "\n" ); document.write( " $\"x%5E2%2B%28-16%2F3%29x-4=0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3x%5E2-16x-12=0\"$ \r
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