document.write( "Question 633555: A chemist is making 200 L of a solution that is 62% acid. He is mixing an 80% acid solution with a 30% acid solution. How much of the 80% acid solution will he use?
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Algebra.Com's Answer #399302 by Maths68(1474)\"\" \"About 
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Mixture
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\n" ); document.write( "Amount=200L
\n" ); document.write( "Concentration=62%=0.62\r
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\n" ); document.write( "\n" ); document.write( "Solution A
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\n" ); document.write( "Amount = x
\n" ); document.write( "Concentration =80% =0.8\r
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\n" ); document.write( "\n" ); document.write( "Solution B
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\n" ); document.write( "Amount = 200-x
\n" ); document.write( "Concentration =30% = 0.3\r
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\n" ); document.write( "\n" ); document.write( "[Amount Solution A * Concentration A] + [Amount Solution B * Concentration of B] = [Amount of Mixture *Concentration of Mixture]
\n" ); document.write( "(x)(0.8)+(200-x)(0.3)=(200)(0.62)
\n" ); document.write( "0.8x+60-0.3x=124
\n" ); document.write( "0.5x=124-60
\n" ); document.write( "0.5x=64
\n" ); document.write( "0.5x/0.5=64/0.5
\n" ); document.write( "x=128\r
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\n" ); document.write( "\n" ); document.write( "Chemist has to mix 128L of the 80% solution with 72L of 30% solution to get a 200L mixture of 62% acid solution..
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