document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=7216>Question 7216</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you do problems like this:<BR>\n" );
document.write( "-[a(-7)] </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #3993 by </B><A HREF=/tutors/aboutme.mpl?userid=elena21><B>elena21(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elena21><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=3993\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> what this problem is saying is that it wants the opposite of \"a\" times \"-7\". so, first you do the inside of the brackets,<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%2A-7 ALIGN=MIDDLE  ALT=\"a%2A-7\"   DISABLED_style= \"max-width:90%; height:auto;\" > and get -(-7a)then you finish the problem by multiplying whats insid ethe parentheses by -1 to get your answer, which is 7a.   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );