document.write( "Question 633939: A chemist mixes 10L of a solution that is 30% acid with 30L of a solution that is 50% acid. What is the percent of acid in the new mixture? \n" ); document.write( "
Algebra.Com's Answer #399299 by Maths68(1474)\"\" \"About 
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\n" ); document.write( "Solution A
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\n" ); document.write( "Amount = 10ml
\n" ); document.write( "Concentration =30% =0.3 \r
\n" ); document.write( "\n" ); document.write( "Solution B
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\n" ); document.write( "Amount = 30ml
\n" ); document.write( "Concentration =50% = 0.5\r
\n" ); document.write( "\n" ); document.write( "Mixture
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\n" ); document.write( "Amount =10+30 = 40ml
\n" ); document.write( "Concentration =x\r
\n" ); document.write( "\n" ); document.write( "[Amount Solution A * Concentration A] + [Amount Solution B * Concentration of B] =[Amount of Mixture *Concentration of Mixture]\r
\n" ); document.write( "\n" ); document.write( "(10)(0.3)+(30)(0.5)=(40)(x)
\n" ); document.write( "3+15=40x
\n" ); document.write( "18=40x
\n" ); document.write( "x=18/40
\n" ); document.write( "x=0.45
\n" ); document.write( "x=45/100=45%\r
\n" ); document.write( "\n" ); document.write( "A chemist mixes 10L of a solution that is 30% acid with 30L of a solution that is 50% acid to prepare 40ml mixture that is 45% acid.
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