document.write( "Question 633939: A chemist mixes 10L of a solution that is 30% acid with 30L of a solution that is 50% acid. What is the percent of acid in the new mixture? \n" ); document.write( "
Algebra.Com's Answer #399299 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Solution A \n" ); document.write( "========= \n" ); document.write( "Amount = 10ml \n" ); document.write( "Concentration =30% =0.3 \r \n" ); document.write( "\n" ); document.write( "Solution B \n" ); document.write( "========= \n" ); document.write( "Amount = 30ml \n" ); document.write( "Concentration =50% = 0.5\r \n" ); document.write( "\n" ); document.write( "Mixture \n" ); document.write( "======== \n" ); document.write( "Amount =10+30 = 40ml \n" ); document.write( "Concentration =x\r \n" ); document.write( "\n" ); document.write( "[Amount Solution A * Concentration A] + [Amount Solution B * Concentration of B] =[Amount of Mixture *Concentration of Mixture]\r \n" ); document.write( "\n" ); document.write( "(10)(0.3)+(30)(0.5)=(40)(x) \n" ); document.write( "3+15=40x \n" ); document.write( "18=40x \n" ); document.write( "x=18/40 \n" ); document.write( "x=0.45 \n" ); document.write( "x=45/100=45%\r \n" ); document.write( "\n" ); document.write( "A chemist mixes 10L of a solution that is 30% acid with 30L of a solution that is 50% acid to prepare 40ml mixture that is 45% acid. \n" ); document.write( " |