document.write( "Question 633948: Question: Mary travels from the city to visit her sister in the country. On the way, she travels 55km/hr. She stays with her sister for 20 hours before starting home. On the return trip, she travels 45 km/hr. She returned home a grand total of 41 hours after she left. How far away, in kilometers, is Mary's house from her sister's?\r
\n" ); document.write( "\n" ); document.write( "What I've managed to reason:
\n" ); document.write( "41 hours total-20 hours visiting=21 hours traveling
\n" ); document.write( "From there, I'm clueless. I've no idea how to start building the equation for this. Help, please?
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Algebra.Com's Answer #399295 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Mary travels from the city to visit her sister in the country. On the way, she travels 55km/hr. She stays with her sister for 20 hours before starting home. On the return trip, she travels 45 km/hr. She returned home a grand total of 41 hours after she left. How far away, in kilometers, is Mary's house from her sister's?
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\n" ); document.write( "City to Country DATA:
\n" ); document.write( "rate = 55 kmh ; time = x hrs ; distance = 55x km
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\n" ); document.write( "Country to Cith DATA:
\n" ); document.write( "rate = 45 kmh ; time = (21-x) hrs ; distance = 45(21-x) km
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\n" ); document.write( "Equation:
\n" ); document.write( "distance = distance
\n" ); document.write( "55x = 45(21-x)
\n" ); document.write( "55x = 45*21 - 45x
\n" ); document.write( "100x = 45*21
\n" ); document.write( "x = 9.45 hrs (time going city to country)
\n" ); document.write( "---
\n" ); document.write( "Distance = 55x = 55*9.45 = 519.75 km
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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