document.write( "Question 633948: Question: Mary travels from the city to visit her sister in the country. On the way, she travels 55km/hr. She stays with her sister for 20 hours before starting home. On the return trip, she travels 45 km/hr. She returned home a grand total of 41 hours after she left. How far away, in kilometers, is Mary's house from her sister's?\r
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document.write( "What I've managed to reason:
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document.write( "41 hours total-20 hours visiting=21 hours traveling
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document.write( "From there, I'm clueless. I've no idea how to start building the equation for this. Help, please? \n" );
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Algebra.Com's Answer #399294 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Mary travels from the city to visit her sister in the country. On the way, she travels 55km/hr. She stays with her sister for 20 hours before starting home. On the return trip, she travels 45 km/hr. She returned home a grand total of 41 hours after she left. How far away, in kilometers, is Mary's house from her sister's?\r \n" ); document.write( "\n" ); document.write( "What I've managed to reason: \n" ); document.write( "41 hours total-20 hours visiting=21 hours traveling \n" ); document.write( "------------ \n" ); document.write( "The avg speed of a round trip = 2*55*45/(55+45) km/hr \n" ); document.write( "= 49.5 km/hr \n" ); document.write( "rt distance = r*t = 49.5*21 km \n" ); document.write( "Each way = 49.5*21/2 = 519.75 km \n" ); document.write( "============ \n" ); document.write( "The avg speed of a round trip = 2*55*45/(55+45) km/hr \n" ); document.write( "You can trust me on that, or I can prove it. \n" ); document.write( " |