document.write( "Question 633892: Find three consecutive odd numbers such that the square of the second number is 192 less than the square of the third number. \r
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\n" ); document.write( "\n" ); document.write( "WE ARE STUDYING POLYNOMIALS AND I NEED SOME HELP WITH THE WORD PROBLEMS PLEASE \n" ); document.write( "
Algebra.Com's Answer #399260 by ankor@dixie-net.com(22740)\"\" \"About 
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Find three consecutive odd numbers such that the square of the second number
\n" ); document.write( " is 192 less than the square of the third number.
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\n" ); document.write( "Let x = the 1st integer, then (x+2) and (x+4) are the next two odd integers
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\n" ); document.write( "Write an equation for the statement:
\n" ); document.write( "\"the square of the second number is 192 less than the square of the third
\n" ); document.write( " number.\"
\n" ); document.write( "(x+2)^2 = (x+4)^2 - 192
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\n" ); document.write( "x^2 + 4x + 4 = x^2 + 8x + 16 - 192
\n" ); document.write( "Combine the variables on the left
\n" ); document.write( "x^2 - x^2 + 4x - 8x = 16 - 192 - 4
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\n" ); document.write( "-4x = -180
\n" ); document.write( "x = \"%28-180%29%2F%28-4%29\"
\n" ); document.write( "x = +45 is the 1st odd number
\n" ); document.write( "then
\n" ); document.write( "47 and 49 are the 2nd and 3rd odd digits
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\n" ); document.write( "Check
\n" ); document.write( "47^2 = 49^2 - 192
\n" ); document.write( "2209 = 2401 - 192\r
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