document.write( "Question 633877: A rectangle is drawn so the width is 17 inches longer than the height. If the rectangle's diagonal measurement is 53 inches, find the height. \n" ); document.write( "
Algebra.Com's Answer #399243 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let represent the width. Then must represent the height. Our good friend and constant companion, Pythagoras, says that the square of the diagonal is equal to the square of the width plus the square of the height:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Collect terms and simplify:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Solve the factorable quadratic for , then calculate \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "John
\n" ); document.write( "
\n" ); document.write( "My calculator said it, I believe it, that settles it
\n" ); document.write( "
\"The

\n" ); document.write( "
\n" ); document.write( "
\n" );