document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=630288>Question 630288</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If (3 over 4 - 2 over 3) + (1 over 2 + 1 over 3) is calculated and the answer reduced to simplest terms, what is the denominator of the resulting fraction? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #399200 by </B><A HREF=/tutors/aboutme.mpl?userid=perfectdose><B>perfectdose(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=perfectdose><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=perfectdose><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=399200\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First thing is to find the common denominator. <BR>\n" );
document.write( "The LCD is 12<BR>\n" );
document.write( "Multiple everything by 12/1<BR>\n" );
document.write( "When you reduce with the denominator, the 'leftovers' go to the numerator. (multiple with whats there)\r<BR>\n" );
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document.write( "9/12-8/12+6/12+4/12= (9-8+6+4=11)<BR>\n" );
document.write( "11/12 </SPAN>\n" );
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