document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=633611>Question 633611</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 58 meters. one side is 3 meters longer than the other side. determine the dimension of the rectangle.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "good day! so i tried this equation: <BR>\n" );
document.write( "let w be the longer side<BR>\n" );
document.write( "let s be the shorter side\r<BR>\n" );
document.write( "\n" );
document.write( "2w+2s=58<BR>\n" );
document.write( "w=3+s<BR>\n" );
document.write( "2(3+s)+s=58<BR>\n" );
document.write( "6+s+s=58<BR>\n" );
document.write( "6+2s=58<BR>\n" );
document.write( "2s=58-6<BR>\n" );
document.write( "2s=52<BR>\n" );
document.write( "(divide both sides by 2)<BR>\n" );
document.write( "s=13\r<BR>\n" );
document.write( "\n" );
document.write( "w=13x3<BR>\n" );
document.write( "w=39\r<BR>\n" );
document.write( "\n" );
document.write( "final answer= 39 and 13 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #399012 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=399012\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Your answer is incorrect and your arithmetic is a little strange, to say the least!<BR>\n" );
document.write( "w = the shorter side.<BR>\n" );
document.write( "s = the longer side.<BR>\n" );
document.write( "s = w+3<BR>\n" );
document.write( "OK so far! Now:<BR>\n" );
document.write( "P = 2(w+s) = 58 Substitute s = w+3 and P = 58.<BR>\n" );
document.write( "58 = 2(w+(w+3)) Simplify.<BR>\n" );
document.write( "58 = 2(2w+3) Divide both sides by 2.<BR>\n" );
document.write( "29 = 2w+3 Subtract 3 from both sides.<BR>\n" );
document.write( "26 = 2w Divide by 2.<BR>\n" );
document.write( "13 = w and s = 13+3 = 16<BR>\n" );
document.write( "Final answer = 16 and 13<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "P = 2(w+s) Substitute w = 13 and s = 16.<BR>\n" );
document.write( "P = 2(13+16) Simplify.<BR>\n" );
document.write( "P = 2(29) <BR>\n" );
document.write( "P = 58 \r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );