document.write( "Question 633559: ``Find the vertices,asymptotes, and the foci of the hyperbola.\r
\n" ); document.write( "\n" ); document.write( "y^(2)-9x^(2)-12y-36x-9=0. \n" ); document.write( "
Algebra.Com's Answer #398984 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
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document.write( "Hi,
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document.write( "y^(2)-9x^(2)-12y-36x-9=0   ⇒ (y-6)^2 - 9(x+2)^2 = 9
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document.write( "\"%28y-6%29%5E2%2F3%5E2+-+%28x%2B2%29%5E2%2F1%5E2+=+1\" C(-2,6)
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document.write( " V(-2, 9) and V(-2,3)
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document.write( "\"F%5Bd%5D+=+sqrt%2810%29\"  Foci (-2, 6 ±\"sqrt%2810%29\") 
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document.write( "Asymptotes: 
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document.write( "     y-6 = 3(x +2)   y = 3x+12
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document.write( "and  y-6 = -3(x+2)   y = -3x 
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document.write( "Standard Form of an Equation of an Hyperbola opening up and down is:
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document.write( "  \"%28y-k%29%5E2%2Fb%5E2+-+%28x-h%29%5E2%2Fa%5E2+=+1\" with C(h,k) and vertices 'b' units up and down from center,  2b the length of the transverse axis
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document.write( "Foci \"sqrt%28a%5E2%2Bb%5E2%29\"units units up and down from center, along x = h
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document.write( "& Asymptotes Lines passing thru C(h,k), with slopes m =  ± b/a
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