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document.write( "Hi,
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document.write( "Re TY, Yes! Good Work!
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document.write( "y^(2)-4x^(2)-6y-32x-59=00 ⇒ (y-3)^2 - 4(x+4)^2 = 4
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C(-4,3)
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document.write( " V(-4, 5) and V(-4,1)
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Foci (-4, 3 ±
)
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document.write( "Asymptotes:
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document.write( " y-3 = 2(x +4) y = 2x +11
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document.write( "and y-3 = -2(x+4) y = -2x -5
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document.write( "Standard Form of an Equation of an Hyperbola opening up and down is:
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with C(h,k) and vertices 'b' units up and down from center, 2b the length of the transverse axis
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document.write( "Foci
units units up and down from center, along x = h
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document.write( "& Asymptotes Lines passing thru C(h,k), with slopes m = ± b/a
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