document.write( "Question 633487: Im having difficulty with solving the following logarithim for X\r
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document.write( "6^(2log base6 X + log base6 X) = 125\r
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document.write( "I thought the log base of 6 would cancel out and I would get \r
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document.write( "x^2 + X =5^3\r
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document.write( "but what do I do with that 6? add it to get X^2 + X +6 =125?
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document.write( "please help thank you \n" );
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Algebra.Com's Answer #398962 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Im having difficulty with solving the following logarithim for X \n" ); document.write( "6^(2log base6 X + log base6 X) = 125 \n" ); document.write( "** \n" ); document.write( "6^(2log base6 X + log base6 X) = 125 \n" ); document.write( "place under single log \n" ); document.write( "6^(log6[(x^2)x])=125 \n" ); document.write( "6^(log6[x^3])=125 \n" ); document.write( "base(6) raised to log of number(x^3)=number(x^3) (definition of logarithm) \n" ); document.write( "x^3=125=5^3 \n" ); document.write( "x=5 \n" ); document.write( ".. \n" ); document.write( "Check: using calculator and change of base formula: \n" ); document.write( "2log base6 X + log base6 X=2log base6(5) + log base6(5)≈2.694733 \n" ); document.write( "6^2.694733≈124.999954.. \n" ); document.write( " |