document.write( "Question 633487: Im having difficulty with solving the following logarithim for X\r
\n" ); document.write( "\n" ); document.write( "6^(2log base6 X + log base6 X) = 125\r
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\n" ); document.write( "\n" ); document.write( "I thought the log base of 6 would cancel out and I would get \r
\n" ); document.write( "\n" ); document.write( "x^2 + X =5^3\r
\n" ); document.write( "\n" ); document.write( "but what do I do with that 6? add it to get X^2 + X +6 =125?
\n" ); document.write( "please help thank you
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Algebra.Com's Answer #398962 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Im having difficulty with solving the following logarithim for X
\n" ); document.write( "6^(2log base6 X + log base6 X) = 125
\n" ); document.write( "**
\n" ); document.write( "6^(2log base6 X + log base6 X) = 125
\n" ); document.write( "place under single log
\n" ); document.write( "6^(log6[(x^2)x])=125
\n" ); document.write( "6^(log6[x^3])=125
\n" ); document.write( "base(6) raised to log of number(x^3)=number(x^3) (definition of logarithm)
\n" ); document.write( "x^3=125=5^3
\n" ); document.write( "x=5
\n" ); document.write( "..
\n" ); document.write( "Check: using calculator and change of base formula:
\n" ); document.write( "2log base6 X + log base6 X=2log base6(5) + log base6(5)≈2.694733
\n" ); document.write( "6^2.694733≈124.999954..
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