document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=58285>Question 58285</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0073016020/algebrahomeworkh>Beginning Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Can someone help me work out this problem?\r<BR>\n" );
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document.write( "  I need to solve the following problem and show the equation used for the solution:\r<BR>\n" );
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document.write( "  Jill has $3.50 in nickels and dimes.  If she has 50 coins, how many of each type of coin does she have?\r<BR>\n" );
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document.write( " Thanks,<BR>\n" );
document.write( "  Ashley </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39894 by </B><A HREF=/tutors/aboutme.mpl?userid=rcmcc><B>rcmcc(152)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rcmcc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rcmcc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39894\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello Ashley,\r<BR>\n" );
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document.write( "we can solve this question by setting up a set of linear equations.\r<BR>\n" );
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document.write( "let the nickels be x and dimes be y\r<BR>\n" );
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document.write( "since we have 50 coins both x+y=50<BR>\n" );
document.write( "because their face value is .05 and .1 and they add up to 3.50 we can state .05x+.1y=3.50\r<BR>\n" );
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document.write( "now we can solve<BR>\n" );
document.write( "x+y=50<BR>\n" );
document.write( ".05x+.1y=3.50<BR>\n" );
document.write( "isolate y in the bottom equation\r<BR>\n" );
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document.write( ".05x+.1y=3.50<BR>\n" );
document.write( "subtract .05x<BR>\n" );
document.write( ".1Y=3.5-.05x<BR>\n" );
document.write( "divide by .1<BR>\n" );
document.write( "y=35-.5X<BR>\n" );
document.write( "now you can substitute in the equation for y in the first equation.\r<BR>\n" );
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document.write( "x+(35-.5x)=50<BR>\n" );
document.write( "you can simplify the equation<BR>\n" );
document.write( ".5x+35=50<BR>\n" );
document.write( "subtract 35 from each side<BR>\n" );
document.write( ".5X=15<BR>\n" );
document.write( "now divide by .5<BR>\n" );
document.write( "x=30\r<BR>\n" );
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document.write( "there are 30 nickels, since you have 50 coins, you have 20 dimes as well.\r<BR>\n" );
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document.write( "we can check this answer\r<BR>\n" );
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document.write( "30(.05)+20(.10)=<BR>\n" );
document.write( "$1.5+2.0=$3.50\r<BR>\n" );
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document.write( " </SPAN>\n" );
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